Newsgroups: sci.astro,sci.answers,news.answers
Subject: [sci.astro] Time (Astronomy Frequently Asked Questions) (3/9)
Followup-To: poster
From: jlazio@patriot.net
Summary: This posting addresses frequently asked questions about time,
calendars, and and related terrestrial phenomena.
Approved: news-answers-request@MIT.EDU
Last-modified: $Date: 2003/07/16 00:00:01 $
Version: $Revision: 4.5 $
URL: http://sciastro.astronomy.net/
Posting-frequency: semi-monthly (Wednesday)
Archive-name: astronomy/faq/part3
------------------------------
Subject: Introduction
sci.astro is a newsgroup devoted to the discussion of the science of
astronomy. As such its content ranges from the Earth to the farthest
reaches of the Universe.
However, certain questions tend to appear fairly regularly. This
document attempts to summarize answers to these questions.
This document is posted on the first and third Wednesdays of each
month to the newsgroup sci.astro. It is available via anonymous ftp
from ,
and it is on the World Wide Web at
and
. A partial list of
worldwide mirrors (both ftp and Web) is maintained at
. (As a general note,
many other FAQs are also available from
.)
Questions/comments/flames should be directed to the FAQ maintainer,
Joseph Lazio (jlazio@patriot.net).
------------------------------
Subject: C.00 Time, Calendars, and Terrestrial Phenomena
[Dates in brackets are last edit.]
C.01 When is 02/01/04? or is there a standard way of writing
dates? [2001-12-14]
C.02 What are all those different kinds of time? [2002-05-07]
C.03 How do I compute astronomical phenomena for my location?
[2002-05-04]
C.04 What's a Julian date? modified Julian date? [1998-05-06]
C.05 Is 2000 a leap year? [2000-03-17]
C.06 When will the new millennium start? [2001-01-01]
C.07 Easter:
07.1 When is Easter? [1996-05-01]
07.2 Can I calculate the date of Easter? [1996-12-11]
C.08 What is a "blue moon?" [2001-10-02]
C.09 What is the Green Flash (or Green Ray)? [1999-01-01]
C.10 Why isn't the earliest Sunrise (and latest Sunset) on the
longest day of the year? [2002-01-30]
C.11 How do I calculate the phase of the moon? [1996-10-08]
C.12 What is the time delivered by a GPS receiver? [2002-05-07]
C.13 Why are there two tides a day and not just one? [1999-12-15]
There is also a calendar FAQ maintained by Claus Tondering
,
.
------------------------------
Subject: C.01 When is 02/01/04? or is there a standard way of writing dates?
Author: Markus Kuhn
The international standard date notation is: YYYY-MM-DD
For example, February 4, 1995 is written as 1995-02-04. This notation
is standardized in International Standard ISO 8601. For more details
regarding this standard, please
.
Other commonly used notations are e.g., 2/4/95, 4/2/95, 4.2.1995,
04-FEB-1995, 4-February-1995, and many more. Especially the first two
examples are dangerous, because as both are used quite often and can
not be distinguished, it is unclear whether 2/4/95 means 1995-04-02 or
1995-02-04.
Advantages of the ISO standard date notation are:
- easily parsed by software (no 'JAN', 'FEB', ... table necessary)
- easily sortable with a trivial string compare
- language independent
- can not be confused with other popular date notations
- consistent with 24h time notation hh:mm:ss which comes also
with the most significant component first and is consequently
also easily sortable (e.g., write 1999-12-31 23:59:59).
- short and has constant length (makes keyboard data entry easier)
- identical to the Chinese date notation, so the largest cultural
group (>25%) on this planet is already familiar with it.
- 4-digit year representation avoids overflow problems after
1999-12-31.
In shell scripts, use
date "+%Y-%m-%d %H:%M:%S"
in order to print the date and time in ISO format. In C, use the
string "%Y-%m-%d %H:%M:%S" as the format specifier for strftime().
Other useful information on the ISO standard is at .
------------------------------
Subject: C.02 What are all those different kinds of time?
Author: Paul Schlyter ,
Markus Kuhn ,
Paul Eggert
In the beginning there were only solar days: sunset was considered to
be the end of the day and the beginning of the next day. The Jewish
and Moslem calendars, which nowadays are used only for religious
purposes, still start a new date at sunset instead of midnight.
Later, the solar days were divided into hours: 12 hours for the day and
12 hours for the night. The different lengths of day/night were ignored,
therefore the daylight hours were longer in summer than in winter.
APPARENT (or TRUE) SOLAR TIME: Still later, the hours were made
equally long: the day+night was 24 hours. The "day" now started at
midnight, not at sunset, which was marked as 00:00 (or 12:00 midnight
in English time format). Noon was at 12:00 (or 12:00 noon in English
time format). This is what we now refer to as "true solar time"---it
is the time shown by a properly setup sundial. This time is local, it
is different for different longitudes. (In strict English
construction, 12:00 cannot be given either an A.M. = ante meridiem or
P.M. = post meridiem designation, but it has become common to use
12 A.M. to mean midnight and 12 P.M. to mean noon. In traditional
English, 12 M. = meridies means _noon_; nowadays one is just as likely
to see 12 M. = midnight and 12 N. = noon.)
(In general, the old English A.M./P.M. notation is extremely
problematic. A shorter and more obvious time notation is the modern
24h notation in which the hours in the day range from 00:00 to 23:59.
This notation even allows one to distinguish midnight at the start of
the day [00:00] from midnight at the end of the day [24:00], while the
old English notation requires kludges like starting a contract at
12:01 A.M. in order to make clear which of the two midnights
associated with a date had been intended. The 24h notation is the
official international standard time notation (ISO 8601) and displayed
by almost all digital clocks outside the U.S.A. The 24h notation is
also recommended by the U.S. Naval Observatory in Washington, which
defines official time in the U.S.)
MEAN SOLAR TIME: True Solar Time isn't a uniform time. The time
difference between one noon and the next noon varies through the year,
due to two causes: 1. The earth's orbit is elliptical, not perfectly
circular, and the Earth's speed in its orbit is greater when closer to
the sun. This makes the solar days shorter in July and longer in
January. 2. The Earth's axis of rotation does not point in the same
direction as the axis of the Earth's orbit round the Sun. (The angle
between these two is called the "obliquity of the ecliptic" and is
about 23.45 degrees.) This makes the solar days shorter in March and
September and longer in June and December. To account for these
effects, a fictitious sun, "The Mean Sun," was invented: it moves with
uniform velocity in the plane of the Earth's equator, with the same
average speed as the true Sun. This Mean Sun defines Mean Solar Time:
When the Mean Sun is due south (for northern hemisphere observers), it
is noon Mean Solar Time. Now the time difference between two
consecutive local noons is always the same (ignoring small
irregularities in the Earth's rotation---more about that later).
SIDEREAL TIME: Closely connected with the Mean Solar Time is the
Sidereal Time, which is defined as the RA (Right Ascension) of the
Local Meridian: when the Vernal Point passes the meridian it is 00:00
Sidereal Time. When Orion is at its maximum altitude, it is between
5h and 6h Sidereal Time; when the Big Dipper can be seen close to the
zenith it is about 12h Sidereal Time; and when Sagittarius, with all
its glories close to the center of our Galaxy, reaches maximum
altitude it is around 18h Sidereal Time. The Sidereal Time at a
particular place and location is the same as the local Mean Solar
Time, plus 12 hours, plus the Right Ascension of the Mean Sun (which
is the same as the Mean Longitude of the true sun). It can be
computed from this formula:
LST(hours) = 6.6974 + 2400.051336 * T + 24 * FRAC(JD+0.5) + long/15
where:
LST = Local Sidereal Time in hours
JD = the Julian Day Number for the moment, including fractions of a day
Note that a new Julian Day starts at Greenwich Noon
T = ( JD - 2451545.0 ) / 36525.0
long = your local longitude: east positive, west negative
FRAC = a function discarding the integral part and returning only the
fractional part of a real number.
STANDARD TIME ZONES: Some 100+ years ago the railway made fast
transportation possible for the first time. Quite soon it became
awkward for the travellers to continually have to adjust their clocks
when travelling between different places, and the railway companies
had the problem to select which city's time to use for their own
schedules. An interim solution was to use a specific "railway time,"
but soon standard time zones were created. At first the time to be
used within a country was the local time of the capital of the
country. A few very large countries employed several time zones. It
took a few decades to arrive at a worldwide agreement here, and in
particular there was a "battle" between England and France whether the
world's prime meridian was to be the meridian of the Greenwich or the
Paris observatory. England won this battle, and "Greenwich Mean Time"
(GMT) was universally agreed upon as the world's standard time zones.
Almost all other parts of the world were assigned time zones, which
usually differ from GMT by an integral number of hours. Some
countries (e.g., India) use differences that are not an integral
number of hours.
GMT (Greenwich Mean Time): This term is a historic term which is in a
strict sense obsolete, though often used (although not in astronomy,
e.g., BBC still uses this abbreviation for patriotic reasons ;-) as a
synonym for UTC. In 1972, an international atomic time scale has been
introduced and since then, the time on the zero meridian, which goes
through the old observatory in Greenwich, London, UK, has been called
Universal Time (UT). Prior to 1925, it was reckoned for astronomical
purposes from Greenwich mean noon (12h UT). Sometimes GMT is referred
to as Z ("Zulu"). (This arises from the military custom of writing
times as hours and minutes run together and suffixed with a single
letter designating the time zone: 2100Z = 21:00 UTC. The word "zulu"
is the phonetic word associated with the letter "z.")
UT (Universal time): Defined by the Earth's rotation and determined by
astronomical observations. This time scale is slightly irregular.
There are several different definitions of UT, but the difference
between them is always less than about 0.03 s. Usually one means UT2
when saying UT. UT2 is UT corrected for pole wandering and seasonal
variations in the Earth's rotational speed.
If you are interested in time more precisely than 1 s, then you'll
have to differentiate between the following versions of Universal
Time:
UT0 is the precise solar local time on the zero meridian. It is today
measured by radio telescopes which observe quasars.
UT1 is UT0 corrected by a periodic effect known as Chandler wobble or
"polar wandering", i.e., small changes in the longitude/latitude
of all places on the Earth due to the fact that the geographical
poles of the Earth "wander" in semi-regular patterns: the poles
follow (very approximately) small circles, about 10--20 meters in
diameter, with a period of approximately 400--500 days. The
changes in the longitude/latitude of all places of Earth due to
this amounts to fractions of an arc second
(1 arc second = 1/3600 degree).
UT2 is an even better corrected version of UT0 which accounts for
seasonal variations in the Earth's rotation rate and is sometimes
used in astronomy.
UTC is a time defined not by the movement of the earth, but by a
large collection of atomic clocks located all over the world, the
atomic time scale TAI. When UTC and UT1 are about to drift apart
more than 0.9 s, a leap second will be inserted (or deleted, but
this never has happened) into UTC to correct this. When necessary,
leap seconds are inserted as the 61th second of the last UTC
minute of June or December. During a leap second, a UTC clock
(e.g., a radio clock such as MSF, HBG, or DCF77) shows:
1995-12-31 23:59:59
1995-12-31 23:59:60
1996-01-01 00:00:00
Today, practically all national civil times are defined relative
to UTC and differ from UTC by an integral number of hours
(sometimes also half- or quarter-hours). UTC is defined in ITU-R
Recommendation TF.460-4 and was introduced in 1972.
If you are interested in UTC more precisely than a microsecond,
then you also have to consider the following differences:
The abbreviation UTC can be followed by an abbreviation of the
organization who publishes this time reference signal.
For example, UTC(USNO) is the US reference time published by the
US Naval Observatory, UTC(PTB) is the official German reference
time signal published (via a 77.5 kHz long-wave broadcast) by the
Physikalisch Technische Bundesanstalt in Braunschweig and
UTC(BIPM) is the most official time published by the Bureau
International des Poids et Mesures in Paris, however UTC(BIPM) is
only a filtered paper clock published each year that is used by
the other time maintainers to resynchronize their clocks against
each other. All these UTC versions do not differ by more than a
few nanoseconds.
The acronym UTC stands for Coordinated Universal Time. In 1970
when this system was being developed by the International
Telecommunication Union, it felt it was best to designate a single
abbreviation for use in all languages in order to minimize
confusion. Unanimous agreement could not be achieved on using
either the English word order, CUT, or the French word order, TUC,
so a compromise using neither, UTC, was adopted.
DUT1 is the difference between UTC and UT1 as published by the US
Naval Observatory rounded to 0.1 s each week. This results in the
UT1 which is used e.g., for space navigation.
ET (Ephemeris Time): Somewhere around 1930--1940, astronomers noticed
that errors in celestial positions of planets could be explained by
assuming that they were due to slow variations on the Earth's
rotation. Starting in 1960, the time scale Ephemeris Time (ET) was
introduced for astronomical purposes. ET closely matches UT in the
19th century, but in the 20th century ET and UT have been diverging
more and more. Currently ET is running almost precisely one minute
ahead of UT. In 1984, ET was replaced by Dynamical Time and TT. For
most purposes, ET up to 1983-12-31 and TDT from 1984-01-01 can be
regarded as a continuous time-scale.
TT and Dynamical Time: Introduced in 1984 as a replacement for ET, it
defines a uniform astronomical time scale more accurately, taking
relativistic effects into account. There are two kinds of Dynamical
Time: TDT (Terrestrial Dynamical Time), which is a time scale tied to the
Earth, and TDB (Barycentric Dynamical Time), used as a time reference
for the barycenter of the solar system. The difference between TDT and
TDB is always smaller than a few milliseconds. When the difference
TDT-TDB is not important, TDT is referred to as TT. For most purposes,
TDT can be considered equal to TAI + 32.184 seconds.
TAI (Temps Atomique International = International Atomic Time):
Defined by the same worldwide network of atomic clocks that defines
UTC. In contrast to UTC, TAI has no leap seconds. TAI and UTC were
identical in the late 1950s. The difference between TAI and UTC is
always an integral number of seconds. TAI is the most uniform time
scale we currently have available.
RELATION BETWEEN THE TIME SCALES
--------------------------------
TDT = TAI+32.184s ==> UT-UTC = TAI-UTC - (TDT-UT) + 32.184s
Starting at TAI-UTC ET/TDT-UT UT-UTC
1972-01-01 +10.00 +42.23 -0.05
1972-07-01 +11.00 +42.80 +0.38
1973-01-01 +12.00 +43.37 +0.81
1973-07-01 -"- +43.93 +0.25
1974-01-01 +13.00 +44.49 +0.69
1974-07-01 -"- +44.99 +0.19
1975-01-01 +14.00 +45.48 +0.70
1975-07-01 -"- +45.97 +0.21
1976-01-01 +15.00 +46.46 +0.72
1976-07-01 -"- +46.99 +0.19
1977-01-01 +16.00 +47.52 +0.66
1977-07-01 -"- +48.03 +0.15
1978-01-01 +17.00 +48.53 +0.65
1978-07-01 -"- +49.06 +0.12
1979-01-01 +18.00 +49.59 +0.59
1979-07-01 -"- +50.07 +0.11
1980-01-01 +19.00 +50.54 +0.64
1980-07-01 -"- +50.96 +0.22
1981-01-01 -"- +51.38 -0.20
1981-07-01 +20.00 +51.78 +0.40
1982-01-01 -"- +52.17 +0.01
1982-07-01 +21.00 +52.57 +0.61
1983-01-01 -"- +52.96 +0.22
1983-07-01 +22.00 +53.38 +0.80
1984-01-01 -"- +53.79 +0.39
1984-07-01 -"- +54.07 +0.11
1985-01-01 -"- +54.34 -0.16
1985-07-01 +23.00 +54.61 +0.57
1986-01-01 -"- +54.87 +0.31
1986-07-01 -"- +55.10 +0.08
1987-01-01 -"- +55.32 -0.14
1987-07-01 -"- +55.57 -0.39
1988-01-01 +24.00 +55.82 +0.36
1988-07-01 -"- +56.06 +0.12
1989-01-01 -"- +56.30 -0.12
1989-07-01 -"- +56.58 -0.40
1990-01-01 +25.00 +56.86 +0.32
1990-07-01 -"- +57.22 -0.04
1991-01-01 +26.00 +57.57 +0.61
1991-07-01 -"- +57.94 +0.24
1992-01-01 -"- +58.31 -0.13
1992-07-01 +27.00 +58.72 +0.46
1993-01-01 -"- +59.12 +0.06
1993-07-01 +28.00 +59.5 +0.7
1994-01-01 -"- +59.9 +0.3
1994-07-01 +29.00 +60.3 +0.9
1995-01-01 -"- +60.7 +0.5
1995-07-01 -"- +61.1 +0.1
1996-01-01 +30.00 +61.63 +0.55
1996-07-01 -"- +62.0 +0.2
1997-01-01 -"- +62.4 -0.2
1997-07-01 +31.00 +62.8 +0.4
1998-01-01 -"- +63.3 -0.1
1998-07-01 -"- +63.7 -0.5
1999-01-01 +32.00 +64.1 +0.1
Additional information about the world time standard UTC (e.g., when
will the next leap second be inserted in time) is available from the
US Naval Observatory and the International Earth Rotation Service
(IERS):
.
Also is a good start if you want
to learn more about time standards.
------------------------------
Subject: C.03 How do I compute astronomical phenomena for my location?
Author: Paul Schlyter
COMPUTING AZIMUTH AND ELEVATION
-------------------------------
To compute the azimuth and elevation of an object, you first must
compute the Local Sidereal Time of the place and time in question.
First convert your local time to UT (Universal Time), with the date
adjusted if needed. Now suppose that the time is Y,M,D,UT where Y,M,D
is the calendar Year, Month (1--12) and Date (1--31), and UT is the
Universal Time in hours+fractions. Also suppose your position is
lat,long, where lat is counted as + if north and - if south, and long
is counted as + if east and - if west. Now, first compute a "day
number", d:
7*(Y + INT((M+9)/12))
d = 367*Y - INT(---------------------) + INT(275*M/9) + D - 730530 + UT/24
4
where INT is a function that discards the fractional part and returns the
integer part of a function. d is zero at 2000 Jan 0.0
Now compute the Local Sidereal Time, LST:
LST = 98.9818 + 0.985647352 * d + UT*15 + long
(east long. positive). Note that LST is here expressed in degrees,
where 15 degrees corresponds to one hour. Since LST really is an angle,
it's convenient to use one unit---degrees---throughout.
Now, suppose your object resides at a known RA (Right Ascension) and
Dec (Declination). Convert both RA and Dec to degrees + decimals,
remembering that 1 hour of RA corresponds to 15 degrees of RA.
Next, compute the Hour Angle:
HA = LST - RA
Now you can compute the Altitude, h, and the Azimuth, az:
sin(h) = sin(lat) * sin(Dec) + cos(lat) * cos(Dec) * cos(HA)
sin(HA)
tan(az) = --------------------------------------------
cos(HA) * sin(lat) - tan(Dec) * cos(Lat)
Here az is 0 deg in the south, 90 deg in the west etc. If you prefer
0 deg in the north and 90 deg in the east, add 180 degrees to az.
A NOTE ON TRIGONOMETRIC FUNCTIONS ON YOUR COMPUTER
--------------------------------------------------
If you have an atan2() function (or equivalent) available on your
computer, compute the numerator and denominator separately and feed
them both to your atan2() function, instead of dividing and feeding
them to your atan() function---then you'll get the correct quadrant
immediately. In the "C" language you would thus write:
az = atan2( sin(HA), cos(HA)*sin(lat)-tan(Dec)*cos(Lat) );
instead of:
az = atan( sin(HA) / (cos(HA)*sin(lat)-tan(Dec)*cos(Lat)) );
On a scientific calculator, there is often a "rectangular to polar"
coordinate conversion function that does the same thing.
Users of Pascal and other programming languages that lack an atan2()
function are strongly encouraged to write such a function of their
own. In Pascal it would be (pi is assumed to have been assigned an
appropriate value---one way is to compute: pi := 4.0*arctan(1) ):
function atan2( y : real, x : real ) real;
(* Compute arctan(y/x), selecting the correct quadrant *)
begin
if x > 0
atan2 := arctan(y/x)
else if x < 0
atan2 := arctan(y/x) + pi
(* Below x is zero *)
else if y > 0
atan2 := pi/2
else if y < 0
atan2 := -pi/2
/* Below both x and y are zero *)
else
atan2 := 0.0 (* atan2( 0.0, 0.0 ) is really an error though.. *)
end
Another trick I also use is to add a set of trig functions that work
in degrees instead of radians to my function library---that will make
life a lot easier when you're working in degrees as the basic unit. I
name them sind, cosd, atan2d, etc. If you don't do that, you'll have
to convert between degrees and radians when calling the standard trig
functions.
COMPUTING RISE AND SET TIMES
----------------------------
To compute when an object rises or sets, you must compute when it
passes the meridian and the HA of rise/set. Then the rise time is
the meridian time minus HA for rise/set, and the set time is the
meridian time plus the HA for rise/set.
To find the meridian time, compute the Local Sidereal Time at 0h local
time (or 0h UT if you prefer to work in UT) as outlined above---name
that quantity LST0. The Meridian Time, MT, will now be:
MT = RA - LST0
where "RA" is the object's Right Ascension (in degrees!). If negative,
add 360 deg to MT. If the object is the Sun, leave the time as it is,
but if it's stellar, multiply MT by 365.2422/366.2422, to convert from
sidereal to solar time. Now, compute HA for rise/set, name that
quantity HA0:
sin(h0) - sin(lat) * sin(Dec)
cos(HA0) = ---------------------------------
cos(lat) * cos(Dec)
where h0 is the altitude selected to represent rise/set. For a purely
mathematical horizon, set h0 = 0 and simplify to:
cos(HA0) = - tan(lat) * tan(Dec)
If you want to account for refraction on the atmosphere, set h0 = -35/60
degrees (-35 arc minutes), and if you want to compute the rise/set times
for the Sun's upper limb, set h0 = -50/60 (-50 arc minutes).
When HA0 has been computed, leave it as it is for the Sun but multiply
by 365.2422/366.2422 for stellar objects, to convert from sidereal to
solar time. Finally compute:
Rise time = MT - HA0
Set time = MT + HA0
convert the times from degrees to hours by dividing by 15.
If you'd like to check that your calculations are accurate or just
need a quick result, check the USNO's Sun or Moon Rise/Set Table,
.
COMPUTING THE SUN'S POSITION
----------------------------
To be able to compute the Sun's rise/set times, you need to be able to
compute the Sun's position at any time. First compute the "day
number" d as outlined above, for the desired moment. Next compute:
oblecl = 23.4393 - 3.563E-7 * d
w = 282.9404 + 4.70935E-5 * d
M = 356.0470 + 0.9856002585 * d
e = 0.016709 - 1.151E-9 * d
This is the obliquity of the ecliptic, plus some of the elements of
the Sun's apparent orbit (i.e., really the Earth's orbit): w =
argument of perihelion, M = mean anomaly, e = eccentricity.
Semi-major axis is here assumed to be exactly 1.0 (while not strictly
true, this is still an accurate approximation). Next compute E, the
eccentric anomaly:
E = M + e*(180/pi) * sin(M) * ( 1.0 + e*cos(M) )
where E and M are in degrees. This is it---no further iterations are
needed because we know e has a sufficiently small value. Next compute
the true anomaly, v, and the distance, r:
r * cos(v) = A = cos(E) - e
r * sin(v) = B = sqrt(1 - e*e) * sin(E)
and
r = sqrt( A*A + B*B )
v = atan2( B, A )
The Sun's true longitude, slon, can now be computed:
slon = v + w
Since the Sun is always at the ecliptic (or at least very very close to
it), we can use simplified formulae to convert slon (the Sun's ecliptic
longitude) to sRA and sDec (the Sun's RA and Dec):
sin(slon) * cos(oblecl)
tan(sRA) = -------------------------
cos(slon)
sin(sDec) = sin(oblecl) * sin(slon)
As was the case when computing az, the Azimuth, if possible use an
atan2() function to compute sRA.
REFERENCES
----------
"Practical Astronomy with your Calculator", Peter Duffet-Smith, 3rd
edition. Cambridge University Press 1988. ISBN 0-521-35699-7.
A good introduction to basic concepts plus many useful algorithms.
The third edition is much better than the two previous editions. This
book is also preferable to Duffet-Smith's "Practical Astronomy with
your Computer", which has degenerated into being filled with Basic
program listings.
"Astronomical Formulae for Calculators", Jean Meeus, 4th ed,
Willmann-Bell 1988, ISBN 0-943396-22-0
"Astronomical Algorithms", Jean Meeus, 1st ed, Willmann-Bell 1991,
ISBN 0-943396-35-2
Two standard references for many kinds of astronomical computations.
Meeus' is an undisputed authority here---many other authors quote his
books. "Astronomical Algorithms" is the more accurate and more modern
of the two, and one can also buy a floppy disk containing software
implementations (in Basic or C) to that book.
------------------------------
Subject: C.04 What's a Julian date? modified Julian date?
Author: Edward Wright ,
William Hamblen
It's the number of days since noon 4713 BC January 1. What's so
special about this date?
Joseph Justus Scaliger (1540--1609) was a noted Italian-French
philologist and historian who was interested in chronology and
reconciling the dates in historical documents. Before the western
civil calendar was adopted by most countries, each little city or
principality reckoned dates in its own fashion, using descriptions
like "the 5th year of the Great Poo-bah Magnaminus." Scaliger wanted
to make sense out of these disparate references so he invented his own
era and reckoned dates by counting days. He started with 4713 BC
January 1 because that was when solar cycle of 28 years (when the days
of the week and the days of the month in the Julian calendar coincide
again), the Metonic cycle of 19 years (because 19 solar years are
roughly equal to 235 lunar months) and the Roman indiction of 15 years
(decreed by the Emperor Constantine) all coincide. There was no
recorded history as old as 4713 BC known in Scaliger's day, so it had
the advantage of avoiding negative dates. Joseph Justus's father was
Julius Caesar Scaliger, which might be why he called it the Julian
Cycle. Astronomers adopted the Julian cycle to avoid having to
remember "30 days hath September ...."
For reference, Julian day 2450000 began at noon on 1995 October 9.
Because Julian dates are so large, astronomers often make use of a
"modified Julian date"; MJD = JD - 2400000.5. (Though, sometimes
they're sloppy and subtract 2400000 instead.)
------------------------------
Subject: C.05 Is 2000 a leap year?
Author: Steve Willner
Yes.
Oh, you wanted to know more?
The reason for leap days is that the year---the time it takes the
Earth to go round the Sun---is not an integral multiple of the
day---the time it takes the Earth to rotate once on its axis. In this
case, the year of interest is the "tropical year," which controls the
seasons. The tropical year is defined as the interval from one spring
equinox to the next: very close to 365.2422 days.
The Julian calendar, instituted by the Roman Emperor Julius Caesar
(who else? :), has a 365-day ordinary year with a 366-day leap year
every fourth year. This gives a mean year length of 365.25 years, not
a very large error. However, the error builds up, and by the
sixteenth century, reform was considered desirable. A new calendar
was established in most Roman Catholic countries in 1582 under the
authority of Pope Gregory XIII; in that year, the date October 4 was
followed by October 15---a correction of 10 days. Most non-Catholic
countries adopted this "Gregorian" calendar somewhat later (Great
Britain and the American colonies in 1752), and by then the difference
between Julian and Gregorian dates was even greater than 10 days.
(Russia didn't adopt the Gregorian calendar until after the "October
Revolution"---which took place in November under the new calendar!)
Many of the calendar changeovers elicited strong emotional reactions
from the populations involved; people objected to "losing ten (or
more) days of our lives."
The rule for leap years under the Gregorian calendar is that all years
divisible by four are leap years EXCEPT century years NOT divisible by
400. Thus 1700, 1800, and 1900 were not leap years, while 2000 will be
one. This rule gives 97 leap years in 400 years or a mean year length
of exactly 365.2425 days.
The error in the Gregorian calendar will build up to a full day in
roughly 3000 years, by which time another reform will be necessary.
Various schemes have been proposed, some taking account of the changing
lengths of the day and/or the tropical year, but none has been
internationally recognized. Leaving a reform to our descendants seems
reasonable, since there is no obvious need to make a correction now.
------------------------------
Subject: C.06 When will the new millennium start?
Author: Steve Willner ,
Paul Schlyter
There is a difference of opinion. Steve Willner writes:
Big "end of millennium" parties were held on 1999-12-31. The
psychological significance of changing the first digit in the year
must not be discounted. (Preceeding these parties were the big
headaches that occurred as everybody rushed to ensure---appropriately
enough---that the date code in everybody's computer did not break on
the next day.) However, the third millennium A.D. in fact begins on
2001-01-01; there was no year zero, and thus an interval of 2000 years
from the arbitrary beginning of "A.D." dates will not have elapsed
until then.
More details may be found in an article by Ruth Freitag in the 1995
March newsletter of the American Astronomical Society. I am seeking
permission to include the article in the FAQ.
A view to the contrary is expressed by Paul Schlyter :
On 2000 January 1 of course! Some people argue that it should be 2001
January 1 just because Roman Numerals lacks a symbol for zero, but I
find that irrelevant, because:
1. Our year count wasn't introduced until A.D. 525---thus the people
who lived at A.D. 1 were completely unaware that we label that
year "A.D. 1."
2. No real known event occurred at either 1 B.C. or A.D. 1---Jesus
was born some 6--7 years earlier. Thus the new millennium
should _really_ have been celebrated already, at least of we
want to celebrate 2000 years since the event that supposedly
started our way of counting years....
(Yes, the Julian calendar _was_ around at 1 B.C. and 1 A.D., but at that
time the years was counted since the "foundation of Rome.")
Interested readers may also want to check the Web sites of The Royal
Observatory Greenwich and the US Naval
Observatory .
------------------------------
Subject: C.07 Easter:
------------------------------
Subject: C.07.1 When is Easter?
Author: Jim Van Nuland ,
John Harper
The "popular" rule (for Roman Catholics and most Protestant
denominations) is that Easter is on the first Sunday after the first
full moon after the March equinox.
The actual rule is similar, except that the astronomical equinox is
not used; the date is fixed at March 21. And the astronomical full
moon is not used; an "ecclesiastical" new moon is determined by
adopted tables based on the Metonic cycle, and "full" is taken as the
14th day of that lunation. There are auxiliary rules that make March
22 the earliest possible date for Easter and April 25 the latest. The
intent of these rules is that the date will be incontrovertibly fixed
and determinable indefinitely in advance. In addition it is
independent of longitude or time zones.
The popular rule works surprisingly well. When the two rules give
different dates, that occurs in only part of the world because two dates
separated by the international date line are simultaneously in progress.
The Eastern Churches (most Orthodox and some others, e.g., Uniate
Churches in Palestine) use the same system, but based on the old
(Julian) calendar. In that calendar, Easter Day is also between March
22 and April 25, but in the western (Gregorian) calendar those days
are at present April 3 and May 8. Whenever the Gregorian calendar
skips a leap year, those dates advance one day.
Some Eastern Churches find both movable feasts like Easter and fixed
ones like Christmas with the Julian calendar; some use the Julian for
movable and the Gregorian for fixed feasts; and the Finnish Orthodox
use the Gregorian for all purposes.
To explain the Eastern system one must begin with the Jews in
Alexandria at the time of the Christian Council of Nicaea in 325, who
appear to have been celebrating Passover on the first "full moon"
after March 21, as specified by the 19-year Metonic cycle and the
Julian calendar (with its leap year every 4 years, end of century or
not). The Bishop of Alexandria was made responsible for the Christian
calendar; he specified that Easter be the Sunday after that Passover.
Eastern Christians still say that Easter must follow Passover, but
that Passover is the one that is meant, not the Passover defined by
the present Jewish calendar.
Subsequently the Jews reformed their calendar (in 358 or in the early
6th century according to different sources; possibly at different
times in different places), in order to improve the fit between
astronomy and their arithmetic, but the Christians did not follow
suit. In 1996, for example, Passover was on April 4 but the Orthodox
Easter was on Sunday April 14, not April 7 (which as it happens was
the Western Easter.)
The Eastern Easter is 0, 1, 4, or 5 weeks after the Western
Easter. The Western Easter can precede the (modern) Jewish Passover,
as in 1967, 1970, 1978, 1986, 1989 and 1997, and can even coincide
with it, as in 1981.
Much of this information was taken from the Explanatory Supplement to
the Astronomical Ephemeris, page 420, 1974 reprint of the 1961
edition. There is more in the Explanatory Supplement, specifically a
series of tables that can be used to determine the Easter date for
both the Julian (Eastern and pre-1582 Western) and Gregorian
calendars. However, the Explanatory Supplement is misleading on the
subject of the Eastern Easters, though its tables are correct.
Jean Meeus has published a program to compute Easter in "Astronomical
Algorithms," also see below. Simon Kershaw has written one in C,
available at .
The most easily available published source for what the Jews
and Christians were doing in ancient Alexandria appears to be Otto
Neugebauer's "Ethiopic Easter Computus" in his _Astronomy and History
Selected Essays_, Springer, New York, 1983, pp. 523--538.
John Harper acknowledges the help of Archimandrite Kyril Jenner, Simon
Kershaw, and Dr. Brian Stewart concerning Eastern Easters.
------------------------------
Subject: C.07.2 Can I calculate the date of Easter?
Author: Bill Jefferys
John Horton Conway (the Princeton mathematician who is responsible for
"the Game of Life") wrote a book with Guy and Berlekamp, _Winning
Ways_, that describes in Volume 2 a number of useful calendrical
rules, including How to Calculate the Day of the Week, Given The Date,
and Easter. Here's a brief precis of how to calculate Easter:
G(the Golden Number) = Year_{mod 19} + 1 (never forget to add the 1!)
C(the Century term) = +3 for all Julian years (i.e., if using the
Julian Calendar)
-4 for 15xx, 16xx }
-5 for 17xx, 18xx } Gregorian
-6 for 19xx, 20xx, 21xx }
The general formula for C in a Gregorian year Hxx is
C = -H + [H/4] + [8*(H+11)/25] (brackets [] mean integer part)
1) The Paschal Full Moon is given by the formula
(Apr 19 = Mar 50) - (11*G+C)_{mod 30}
Except when the formula gives Apr 19 you should take Apr 18, and when it
gives Apr 18 and G>=12 you should take Apr 17. Easter is then the
following Sunday, since Easter always falls on the next Sunday that is
_strictly later_ than the Paschal Full Moon.
Example: 1945 = 7 mod 19, so G = 8 and we find for the Paschal Full Moon
Mar 50 - (88-6)_{mod 30} = Mar 50 - 22 = Mar 28.
This happens to be a Wednesday (by Horton's "Doomsday" rule for Day of
the Week, see below). Therefore, Easter 1945 took place on Sunday,
April 1.
Conway's "Doomsday" method for finding the day of the week, given the
date, is needed for his Easter method.
To every year there is a distinguished day of the week, which Conway
calls the "Doomsday", D. In any year, if March 0 (the last day of
February) falls on a particular DOW, then the following dates also
fall on the same DOW: 4/4, 6/6, 8/8, 10/10, 12/12. Also 5/9, 9/5,
7/11, 11/7 (for which he has devised the mnemonic "I went to my
nine-to-five job at the Seven-Eleven. Note to non-US readers:
"Seven-Eleven" is the name of a ubiquitous chain of convenience
stores.) In non-leap years, Jan 3 and Feb 0 (Jan 31) also fall on
that DOW; in leap years, Jan 4 and Feb 1. Conway calls this DOW the
"doomsday" for that year.
For example, in 1995 Doomsday is Tuesday. Columbus Day (10/12) is two
days after 10/10, a Tuesday, so 10/12 is a Thursday.
All that remains is a rule for calculating the Doomsday for any year.
In any century, this is done by taking the last two digits of the
year, call them xx, dividing by 12 to get a quotient Q and remainder
R. Divide R by 4 to get a second quotient Q2. Then this century,
the Doomsday for that year is given by Wednesday + Q + R + Q2. In
1995, for example, we have 95/12 = 7 with remainder 11; 11/4 gives
quotient 2; Wednesday + 7 + 11 + 2 = Tuesday (cf. above).
In other years on the Gregorian calendar, one uses instead of
Wednesday, the century day as follows: 16xx and 20xx: Tuesday; 17xx
and 21xx: Sunday; 18xx and 22xx: Friday; 15xx, 19xx and 23xx:
Wednesday. The cycle repeats over a 4 century period.
If you need the DOW on the Julian calendar, the rules are the same
except that the century rule is different: for a date in the year ccxx,
use -cc for the century day of week, where Sunday = 0. For example,
October 4, 1582 (the last day of the Julian calendar in countries that
followed Pope Gregory's institution of the Gregorian calendar) took
place as follows:
82/12 = 6 remainder 10; 10/4 gives remainder 2; 6+10+2-15= 3,
which is Wednesday. 10/10 was Wednesday, 10/3 was Wednesday, so
10/4/1582 (Julian) was a Thursday.
The following day was October 15, 1582 (Gregorian). Again we
can check: 6+10+2+Wed = Sunday. 10/10 was a Sunday (Gregorian)
so 10/15/1582 (Gregorian) was a Friday.
The nice thing about these algorithms is that they can easily be done in
one's head with a little practice (OK, mod 19 for the Golden Number is a
bit hairy for me, but I can still do it!). The DOW calculation is very
useful if you are caught without a calendar, and it makes a good party
trick.
Additional information is available at
and
.
------------------------------
Subject: C.08 What is a "blue moon?"
Author: Steve Willner ,
Jay Respler
Colloquially the term "blue moon" is used to mean "a very long time."
In fact, there have been at least seven different uses of the term
"blue moon" in the past several hundred years.
The alt.usage.english FAQ discusses these different meanings of the
term "blue moon." The two definitions most relevant to astronomy are
the following:
1. Under certain conditions of atmospheric haze, the moon may actually
look blue. A notable example occurred after the explosion of the
volcano Krakatoa. The appropriate conditions are extremely rare.
2. The second full moon in a calendar month. Since the synodic month
is 29.53 days, this kind of blue moon occurs roughly once out of 60
30-day months and once out of 21 31-day months or about once in 2.5
years on average. It can occur in January and the following March if
there is no full moon at all in February. There are some indications
that some calendars used to put the first moon in the month in red,
the second in blue, hence the origin of the term.
Philip Hiscock, writing in the 1999 March issue of Sky & Telescope,
expands upon the history of this definition. This definition of "blue
moon" is of fairly recent vintage and came into widespread use in the
late 1980s as a result of the board game Trivial Pursuit. He was able
to trace its origin to an (incorrect) entry in the 1937 edition of the
_Maine Farmer's Almanac_.
The alt.usage.english FAQ is available from
or
.
------------------------------
Subject: C.09 What is the Green Flash (or Green Ray)?
Author: Steve Willner ,
Geoffrey A. Landis
When the sun sets, sometimes the last bit of light from the disk itself
is an emerald green. The same is true of the first bit of light from
the rising sun. This phenomenon is known as the "green flash" or "green
ray." It is not an optical illusion.
The green flash is common and will be visible any time the sun is
rises or sets on a *clear*, *unobstructed*, and *low* horizon. From
our observatory at Mt. Hopkins, I (SW) see the sunset green flash
probably 90% of the evenings that have no visible clouds on the
western horizon. It typically lasts one or two seconds (by estimate,
not stopwatch) but on rare occasions much longer (5 seconds??). I've
seen the dawn green flash only once, but a) I'm seldom outside
looking, b) the topography is much less favorable, and c) it takes
luck to be looking in exactly the right place. If you'd like to see
the green flash, the higher you can go, the better (see below).
The explanation for the green flash involves refraction, scattering,
and absorption. First, the most important of these processes,
refraction: light is bent in the atmosphere with the net effect that
the visible image of the sun at the horizon appears roughly a solar
diameter *above* the geometric position of the sun. This refraction
is mildly wavelength dependent with blue light being refracted the
most. Thus if refraction were the only effect, the red image of the
sun would be lowest in the sky, followed by yellow, green, and blue
highest. If I've understood the refraction table properly, the
difference between red and blue (at the horizon) is about 1/40 of a
solar diameter.
Now scattering: the blue light is Rayleigh scattered away (not Compton
or Thomson scattering).
Now absorption: air has a very weak absorption band in the yellow.
When the sun is overhead, this absorption hardly matters, but near the
horizon, the light travels through something like 38 "air masses," so
even a weak absorption becomes significant.
The explanation for the green flash is thus, 1) refraction separates
the solar images by color; 2) at just the right instant, the red image
has set, 3) the yellow image is absorbed; and 4) the blue image is
scattered away. We are left with the upper limb of the green image.
Because the green flash is primarily a refraction effect, it lasts
longer and is easier to see from a mountain top than from sea level.
The amount of refraction is proportional to the path length through
the atmosphere times the density gradient (in a linear approximation
for the atmosphere's index of refraction). This product will scale
like 1+(h/a)^(0.5), where h is your height and a the scale height of
the atmosphere. The density scale height averaged over the bottom
10 km of the atmosphere is about 9.2 km, so for a 2 km mountain the
increase in refraction is about a factor 1.5; a 3 km mountain gives
1.6 and a 4.2 km mountain (e.g., Mauna Kea) gives 1.7.
More details can be found in _The Green Flash and Other Low Sun
Phenomena_, by D. J. K. O'Connell and the classic _Light and Color in
the Open Air_. A refraction table appears in _Astrophysical
Quantities_, by C. W. Allen. There's also an on-line resource at
.
------------------------------
Subject: C.10 Why isn't the earliest Sunrise (and latest Sunset) on the
longest day of the year?
Author: Steve Willner
This phenomenon is called the "equation of time." This is just a
fancy name for the fact that the Sun's speed along the Earth's equator
is not constant. In other words, if you were to measure the Sun's
position at exactly noon every day, you would see not only the
familiar north-south change that goes with the seasons but also an
east-west change in the Sun's position. A graphical representation of
both positional changes is the analemma, that funny figure 8 that most
globes stick in the middle of the Pacific ocean.
The short explanation of the equation of time is that it has two
causes. The slightly larger effect comes from the obliquity of the
ecliptic---the Earth's equator is tilted with respect to the orbital
plane. Constant speed along the ecliptic---which is how the "mean
sun" moves---translates to varying speed in right ascension (along the
equator). This gives the overall figure 8 shape of the analemma.
Almost as large is the fact that the Earth's orbit is not circular,
and the Sun's angular speed along the ecliptic is therefore not
constant. This gives the inequality between the two lobes of the
figure 8.
Some additional discussion, with illustrations, is provided by Nick
Strobel at
, though
you may want to start with the section on time at
.
Mattthias Reinsch provides an analytic expression for determining the
number of days between the winter solstice and the day of the latest
sunrise for Northern Hemisphere observers,
.
The Earth's analemma will change with time as the Earth's orbital
parameters change. This is described by Bernard Oliver (1972 July,
_Sky and Telescope_, pp. 20--22)
An article by David Harvey (1982 March, _Sky and Telescope_,
pp. 237--239) shows the analemmas of all nine planets. A simulation
of the Martian analemma is at
, and illustrations
of other planetary analemmas is at .
------------------------------
Subject: C.11 How do I calculate the phase of the moon?
Author: Bill Jefferys
John Horton Conway (the Princeton mathematician who is responsible for
"the Game of Life") wrote a book with Guy and Berlekamp, _Winning
Ways_, that describes in Volume 2 a number of useful calendrical
rules. One of these is an easy "in your head" algorithm for
calculating the phase of the Moon, good to a day or better depending
on whether you use his refinements or not.
In the 20th century, calculate the remainder upon dividing the
last two digits of the year by 19; if greater than 9, subtract
19 from this to get a number between -9 and 9.
Multiply the result by 11 and reduce modulo 30 to obtain a
number between -29 and +29.
Add the day of the month and the number of the month (except
for Jan and Feb use 3 and 4 for the month number instead of
1 and 2).
Subtract 4.
Reduce modulo 30 to get a number between 0 and 29. This is
the age of the Moon.
Example: What was the phase of the Moon on D-Day (June 6,
1944)?
Answer: 44/19=2 remainder 6.
6*11=66, reduce modulo 30 to get 6.
Add 6+6 to this and subtract 4: 6+6+6-4=14; the Moon was (nearly)
full. I understand that the planners of D-day did care about the phase
of the Moon, either because of illumination or because of tides. I
think that Don Olsen recently discussed this in _Sky and Telescope_
(within the past several years).
In the 21st century use -8.3 days instead of -4 for the last number.
Conway also gives refinements for the leap year cycle and also
for the slight variations in the lengths of months; what I have
given should be good to +/- a day or so.
------------------------------
Subject: C.12 What is the time delivered by a GPS receiver?
Author: Markus Kuhn
Navstar GPS (global positioning system) is a satellite based
navigation system operated by the US Air Force. The signals broadcast
by GPS satellites, contain all information required by a GPS receiver
in order to determine both UTC and TIA highly accurately. Commercial
GPS receivers can provide a time reference that is closer than 340 ns
to UTC(USNO) in 90% of all measurements, classified military versions
are even better.
------------------------------
Subject: C.13 Why are there two tides a day and not just one?
Author: Joseph Lazio ,
Paul Zander
An easy way to think of the Moon's effect on the Earth is the
following. The Moon exerts a gravitational force on the Earth. The
strength of the gravitational force decreases with increasing
distance. So, because the surface of the ocean is closer to the Moon
than the sea floor, the surface water is attracted more strongly to
the Moon. That's the tide that occurs (nearly) under the Moon.
What's happening on the other side of the Earth? On the other side of
the Earth from the Moon, the sea floor is being pulled more strongly
toward the Moon than the surface water. In essence, the surface water
is being left behind. Voila, another bulge in the surface water and
another tide.
In principle, there should be two tides of equal height in a day. In
practice, many parts of the earth do not experience two tides of equal
height in a day.
First, because the Moon's orbit is at an angle to the Earth's equator,
one tidal bulge may be in the northern hemisphere, while the other is
in the southern hemisphere.
Except around Antarctica, the shape of the Earth's continents prevent
the tidal bulges from simply following the moon. Each ocean basin has
its own individual pattern for the tidal flow. In the South Atlantic
Ocean, the tides travel from south to north, taking about 12 hours to
go from the tip of Africa to the equator.
In the North Atlantic, the tides travel in a counter-clockwise
direction going around once in about 12 hours. The effect is similar
to water sloshing around in a bowl. Because the two tides are roughly
equal, they are called semidaily or semidiurnal.
In some parts of the Gulf of Mexico, there is only one high tide and
one low tide a day. These are called daily or diurnal tides. In much
of the Pacific Ocean, there are two high tides and two low tides each
day, but they are of unequal height. These are called mixed tides.
The traditional way to predict tides has been to collect data for
several years to have enough combinations of positions of the moon and
sun to allow accurate extrapolation. More recently, computer models
have been made taking into account detailed shapes of the ocean
bottoms and coastlines.
Even the best predictions can have difficulties. The extremely heavy
snow fall during the winter of 1994--95 in California and the
associated run-off as it melted were not part of the model for San
Francisco Bay. Sail boat races scheduled to take advantage of tidal
currents coming into the Golden Gate found the current was still going
out!
Ref: Oceanography, A View of the Earth, M. Grant Gross, Prentice Hall,
Englewood Cliffs, New Jersey, 1972.
For even more details, see
and
.
------------------------------
Subject: Copyright
This document, as a collection, is Copyright 1995--2003 by T. Joseph
W. Lazio (jlazio@patriot.net). The individual articles are copyright
by the individual authors listed. All rights are reserved.
Permission to use, copy and distribute this unmodified document by any
means and for any purpose EXCEPT PROFIT PURPOSES is hereby granted,
provided that both the above Copyright notice and this permission
notice appear in all copies of the FAQ itself. Reproducing this FAQ
by any means, included, but not limited to, printing, copying existing
prints, publishing by electronic or other means, implies full
agreement to the above non-profit-use clause, unless upon prior
written permission of the authors.
This FAQ is provided by the authors "as is," with all its faults. Any
express or implied warranties, including, but not limited to, any
implied warranties of merchantability, accuracy, or fitness for any
particular purpose, are disclaimed. If you use the information in
this document, in any way, you do so at your own risk.